Hamiltonian Path via ∃ M ⊆ E

Prompt (Question • Data • Logic)

Question.
Does the undirected graph G=(V,E) have a Hamiltonian path?
Data.
V = {a,b,c,d,e,f}
E = { a—b, b—c, c—d, d—e, e—f, b—d }
Logic (Second-Order).
∃ M ⊆ E. |M|=|V|−1 ∧ connected(M) ∧ deg_M endpoints = {1,1} ∧ others = {2}
The witness M is a subset of edges (a second-order variable).

Answer

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Reason Why

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Checks (at least 5)

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Diagnostics

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